| CCNA Planning & Designing topic explains all the | | | | D. 115.64.3.255 E. 115.64.5.128 F. 115.64.12.128 |
| actual and real questions that would be on ccna | | | | Answer: BCE |
| test. | | | | Explanation: /22 is 8bits + 8bits + 6bits i.e |
| Question 1: Which of the following host addresses | | | | 11111111.11111111.11111100.0 Third octet 11111100 = |
| are members of networks that can be routed | | | | 128+64+32+16+8+4 = 252 therefore subnet |
| across the public Internet?(Choose three.) A. | | | | mask is 255.255.252.0 Subnet networks are |
| 10.172.13.65 B. 172.16.223.125 C. 172.64.12.29 D. | | | | 256-252= 4 Host range for above subnet are |
| 192.168.23.252 E. 198.234.12.95 F. 212.193.48.254 | | | | 0------- 3 4 ------ 7 |
| Answer: CEF | | | | Host that fall under 115.64.4.0 /22 networks are 4 |
| Explanation: Private IP address scheme Class A: | | | | 5 6 7 |
| 10.0.0.0 – 10.255.255.255 Class B: 172.16.0.0 | | | | Question 6: In the implementation of VLSM |
| – 172.31.255.255 Class C: 192.168.0.0 – | | | | techniques on a network using a single Class C IP |
| 192.168.255.255 Other then private ip addresses | | | | address, which subnet mask is the most efficient |
| remaining IP’s addresses are routed across | | | | for point-to-point serial links? A. 255.255.255.0 B. |
| internet. | | | | 255.255.255.240 C. 255.255.255.248 D. |
| Question 2: Given a subnet mask of | | | | 255.255.255.252 E. 255.255.255.254 |
| 255.255.255.224, which of the following addresses | | | | Answer: D |
| can be assigned to network hosts? (Choose | | | | Explanation: For point-to-point serial link exist only |
| three.) A. 15.234.118.63 B. 92.11.178.93 C. | | | | two hosts so the best possible subnet mask for |
| 134.178.18.56 D. 192.168.16.87 E. 201.45.116.159 F. | | | | two useable hosts for class C network is |
| 217.63.12.192 | | | | 255.255.255.252 |
| Answer: BCD | | | | Question 7: Which statements are true regarding |
| Explanation: For calculating network hosts range | | | | classless routing protocols? (Choose two.) A. The |
| for subnet 255.255.255.224 Simple method to find | | | | use of discontiguous subnets is not allowed. B. The |
| out network subnet is 256 -224 = 32 Write down | | | | use of variable length subnet masks is permitted. |
| the multiples of 32 to get subnet networks Host | | | | C. RIP v1 is a classless routing protocol. D. IGRP |
| range for subnet 255.255.255.224 are between | | | | supports classless routing within the same |
| this ranges below 0 ----- 31 (0 is network address | | | | autonomous system. E. RIP v2 supports classless |
| and 31 is broadcast address) 32 -----63 64 -----95 | | | | routing. |
| 96 -----127 128 ----159 160---- 191 192 ----223 224 | | | | Answer: BE |
| ----255 | | | | Question 8: |
| Question 3: When variable length subnet masking | | | | The company internetwork is subnetted using 29 |
| is used, what does the term route aggregation | | | | bits. Which wildcard mask should be used to |
| describe? A. calculating the total number of | | | | configure an extended access list to permit or |
| available host addresses in the AS B. combining | | | | deny access to an entire subnetwork? A. |
| routes to multiple networks into one supernet C. | | | | 255.255.255.224 B. 255.255.255.248 C. 0.0.0.224 D. |
| reducing the number of unusable addresses by | | | | 0.0.0.8 E. 0.0.0.7 F. 0.0.0.3 |
| creating many subnets from one supernet D. | | | | Answer: E |
| reclaiming unused address space by changing the | | | | Explanation: 29 bits subnet is 8bits + 8bits + 8bits |
| subnet size | | | | + 5bits 255.255.255.(5bits) 11111000 = |
| Answer: B | | | | 128+64+32+16+8+0+0+0 = 248 Subnet is |
| Explanation: Route aggregration is an effort to | | | | 255.255.255.248 Simple method to calculate the |
| route smaller prefixes via an aggregated larger | | | | Wildcard mask from known subnet is to Reverse |
| prefix (supernetting). The advantage is obvious: | | | | 1’s into 0’s and 0’s into 1’s from |
| Many /24 networks, for example, could be | | | | the binary representation of subnet. For above |
| aggregated to larger networks like /23, /22 or | | | | example (248 = 11111000 subnet) 11111000 |
| even bigger prefixes. | | | | (subnet) = 00000111 (wildcard mask) last octet. = |
| Question 4: ABC Company is merging with | | | | 7 (wildcard mask) for last octet. Converting the |
| several local businesses that use routers from | | | | remaining first 3 octets of subnet into wildcard |
| multiple vendors. Which routing protocol would | | | | mask using above method Resulted wildcard |
| work best to connect ABC Company with the | | | | mask is 0.0.0.7 |
| enterprise networks it has acquired by providing | | | | Question 9: The MDA Company is implementing |
| scalability and VLSM support while minimizing | | | | dialup services to enable remote office employees |
| network overhead? | | | | to connect to the local network. The company |
| A. RIP v1 B. RIP v2 C. IGRP D. OSPF E. EIGRP | | | | uses several different Layer 3 protocols on the |
| Answer: D | | | | network. Authentication of the users connecting |
| Explanation: Since only OSPF,EIGRP and RIPv2 | | | | to the network is required for security. |
| supports VLSM in above options. It requires | | | | Additionally, some employees will be dialing long |
| working with multi vendor and providing scalability | | | | distance and will need callback support. Which |
| OSPF is best choice of the three mentioned. | | | | protocol is the best choice for these remote |
| Question 5: Which of the following IP addresses | | | | access services? A. 802.1 B. Frame relay C. HDLC |
| fall into the CIDR block of 115.64.4.0/22? (Choose | | | | D. PPP E. SLIP F. |
| three.) A. 115.64.8.32 B. 115.64.7.64 C. 115.64.6.255 | | | | |